Parametric form of Circle

x = r cos
, y = r sin
,0
< 2
represent the circle x² +y²
= r², where
is called parameter and the point P
(r cos
, r sin
) is called the point
"
" on the circle x² +y² = r².
Parametric form of the circle (x -h)² +(y -k)² = r²
Every point P on the circle can be represented as
x = h + r cos
, y = k + r
sin
, 0
< 2
![]()
Thus, x = h + r cos
, y = k + r sin
, 0
< 2
, represent the circle (x -h)² +(y -k)² = r².
is called parameter and the point (h +r cos
,
k +r sin
) is called the point "
" on
this circle.
Illustrative Examples
Example
Find the parametric equations of the circle x² +y² = 5
Solution
The given circle is x² + y² = 5
We know that the parametric equations of the circle x² +y² = r² are
x = r cos
, y = r sin
, 0
< 2
![]()
The given circle is comparable with x² +y² = r², here
r =
5
Therefore, the parametric equations of the given circle x² +y² = 5 are
x =
5cos
, y =
5 sin
, 0
< 2 ![]()
Example
Find the cartesian equations of the curves x = p +c cos
, y = q +c sin
, where
is parameter. Do these equations represent a circle? If
so, find center and radius.
Solution
Given x = p +c cos
,
y = q + c sin ![]()
=> x -p = c cos
,
y -q = c sin ![]()
To eliminate the parameter
, on squaring and adding these
equations, we get
(x -p)² + (y -q)² = c² (cos²
+sin²
)
=> (x -p)² +(y -q)² = c²,
which represents a circle with center (p, q) and radius = | c |.
Exercise
- Find the parametric equations of the following circles :
(i) x² +y² = 13
(ii) (x -2)² +(y +3)² = 36
(iii) x² + y² +4 x - 6 y -12 = 0
(iv) 2 x² +2 y² = 5 x +7 y +3
(v) x² + y² -2 a x - 2 a y = 0
(vi) x² + y² + p x +q y = 0 - Find the cartesian equations of the following curves:
(i) x = 2 cos
, y = 2 sin 
(ii) x = 1 +5 cos
, y = 2 +5 sin 
(iii) x = -3 +
7cos
, y = 4 +
7
sin
,
where
is parameter. Do these equations represent
circles? If so, find center and radius.
Answers
1. (i) x =(ii) x = 2 +6 cos
(iii) x = -2 +5 cos
(iv) x = cos
(v) x = a +| a | cos
(vi) x = -p/2 +(1/2)
2. (i) x² +y² = 4; circle, (0, 0), 2
(ii) (x -1)² +(y -2)² = 25; circle, (1, 2), 5
(iii) (x +3)² +(y -4)² = 7; circle, (-3 , 4),
